Q. 245.0( 3 Votes )

# In the given figure, AB || CD. If ∠CAB = 80° and ∠EFC = 25°, then ∠CEF = ?

A. 65°

B. 55°

C. 45°

D. 75°

Answer :

AB || CD

BAC = DCF = 80^{o}

ECF + DCF = 180^{o} (linear pair of angles)

ECF =100^{o}

Now in triangle CFE,

ECF + EFC + CEF = 180^{o}

CEF = 180^{o} – 100^{o} – 25^{o}

=55^{o}

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