Q. 245.0( 3 Votes )

In the given figure, AB || CD. If CAB = 80° and EFC = 25°, then CEF = ?


A. 65°

B. 55°

C. 45°

D. 75°

Answer :

AB || CD


BAC = DCF = 80o


ECF + DCF = 180o (linear pair of angles)


ECF =100o


Now in triangle CFE,


ECF + EFC + CEF = 180o


CEF = 180o 100o – 25o


=55o

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