Q. 244.6( 19 Votes )

In Fig., ∠<

Answer :

Given: X = 62o, XYZ = 54o


YO and ZO are the bisectors of XYZ and XZY respectively.


To Find OZY and YOZ.


Now, according to the question,


X + XYZ + XZY = 180o(Sum of the interior angles of a triangle = 180°)


62o + 54o + XZY = 180o


116o + XZY = 180o


XZY = 64o


Now,


As ZO is the bisector of XZY


OZY = 1/2 XZY


OZY = 32o


And,


As YO is bisector of XYZ


OYZ = 1/2 XYZ


OYZ = 27o


Now,


OZY + OYZ + O = 180o(Sum of the interior angles of the triangle = 180°)


32o + 27o + O = 180o


59o + O = 180o


O = 121o


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