Q. 244.5( 2 Votes )

Find: <span

Answer :



[Applying the formula: sinθ + cos2 θ = 1]



Let sinθ = t

Differentiating both sides we get,

cosθ dθ = dt



put t2 = y and do the partial fractions,



1 = A(4y + 1) + B(y + 4) = (4A + B)y + (A + 4B)


Comparing coefficients of y on both sides-


4A + B = 0 ...(1)


Also compare constant terms-


A + 4B = 1 ...(2)


On solving (1) & (2), we get-


A = -(1/15) & B = (4/15)








put t = sinθ



Answer.

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