Q. 235.0( 1 Vote )

Using properties

Answer :

Let’s Take L.H.S

L.H.S =

Taking x, y and z common from R1 , R2 and R3 in the second determinant

Applying R2 - >R2 - R1 and R3 - >R2 - R1 , we get

Taking (y - x)(z - x) then , we get

Now, Expanding along Coloumn1

Hence, Proved


Given, A =

To find: Find the inverse of the A

Explanation: We have given, A =

We know, A = IA

Where I is the Identity Matrix

Applying R2 - >R2 + R1

Applying R2 - > R2 + 2R3

Applying R1R1 - 2R2 and R3R3 + 2R2

Applying R1R1 + 2R3

Hence, This is the inverse of Matrix

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

If <span lang="ENMathematics - Board Papers

Using matrices soMathematics - Board Papers

<span lang="EN-USMathematics - Board Papers

Using properties Mathematics - Board Papers

Using matrices, sMathematics - Board Papers

If A is square maMathematics - Exemplar

If <span lang="ENMathematics - Exemplar

The management coMathematics - Board Papers

If A is an invertMathematics - Board Papers

If <iMathematics - Board Papers