There is a narrow

Let the length and breadth of the plot be l = 11 x and b = 4 x respectively.

Since the plot is of rectangular shape and we know  the perimeter of a rectangle is 2(l + b)

Also, rate of fencing the plot is Rs 100 for 1m

Now,

Perimeter of Rectangular plot = 2(l + b) = 2 (11 x + 4 x)

Perimeter of rectangular plot =  2(15 x) = 30 x

Cost of fencing one meter = Rs. 100

Therefore cost of fencing 30 x m = 30 x × 100 = 75000

3000 x = 75000

x = 25

Thus, the length = 11 x (25) = 275 m

And the breadth = 4 x (25) = 100 m