Answer :

Given, length of cuboidal pond = 20m

breadth of cuboidal pond = 18.5 m


height of cuboidal pond = 3.2m


Thus volume of cuboidal pond = length × breadth × height


= 20×18.5×3.2


= 1184 m3


According to question, time required to irrigate upto 160 L = 1 hr


As, 1m3 = 1000L


160L = = 0.16 m3


So, time required to irrigate 1184 m3 hr.



= 7400 hr


2nd part: Length of field = 59.2m


breadth of field = 40 m


Let height of field = H m


According to question,


Volume of field to be poured with water = volume of water


length ×breadth × height = 1184 m3


59.2 × 40 × H = 1184


H =


H = 0.5 m


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