Q. 234.3( 16 Votes )

# The depth of a cu

Answer :

Given, length of cuboidal pond = 20m

breadth of cuboidal pond = 18.5 m

height of cuboidal pond = 3.2m

Thus volume of cuboidal pond = length × breadth × height

= 20×18.5×3.2

= 1184 m^{3}

According to question, time required to irrigate upto 160 L = 1 hr

As, 1m3 = 1000L

160L = = 0.16 m^{3}

So, time required to irrigate 1184 m^{3} hr.

= 7400 hr

2^{nd} part: Length of field = 59.2m

breadth of field = 40 m

Let height of field = H m

According to question,

Volume of field to be poured with water = volume of water

length ×breadth × height = 1184 m^{3}

59.2 × 40 × H = 1184

H =

H = 0.5 m

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