Answer :
Given: binary operation * on A = R – {-1} defined as
a * b = a + b + ab for all a and b belongs to A
To prove: given operation is is commutative and associative on A and every element of A is invertible.
To find: the identify element of * in A
Commutativity:
a * b = a + b + ab and b * a = b + a + ba
Since, a + b + ab = b + a + ba
⇒ a * b = b * a
This shows that operation is commutative
Associativity:
(a * b) * c
= (a + b + ab) * c
= a + b + ab + c + (a + b + ab)c
= a + b + ab + c + ac + bc + abc……………(1)
and
a * (b * c)
= a * (b + c + bc)
= a + b + c + bc + a(b + c + bc)
= a + b + c + bc + ab + ac + abc………………(2)
Since, (1) = (2)
⇒ (a * b) * c = a * (b * c)
This shows that operation is associative
Existence of identity:
Let e be the identity element
a * e = a = e * a
⇒ a + e + ae = a and e + a + ea = a
⇒ e(1 + a) = a – a
⇒ e(1 + a) = 0
⇒ e = 0
So, 0 is the identity element of the * operation
Existence of inverse:
a * b = e = e * b
⇒ a + b + ab = 0
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