Q. 235.0( 1 Vote )

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Answer :

Given that f : R R be a function where



Here, we can see that for negative as well as positive x we will get same value.


So, it is not one-one.


y = f(x)



y(x2 + 2) = (x2 – 8)


x2(y-1)=- 2y – 8



For y = 1 , no x is defined.


So, f is not onto.

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