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Given that f : R → R be a function where

Here, we can see that for negative as well as positive x we will get same value.

So, it is not one-one.

y = f(x)

⇒ y(x² + 2) = (x² – 8)

⇒ x²(y-1)=- 2y – 8

For y = 1 , no x is defined.

So, f is not onto.