Q. 233.8( 13 Votes )

# In the given figu

Answer :

Given: ABCD is a trapezium, ABDC, AB = a cm and DC = b cm, E and F are the midpoints of AD and BC.

Since E and F are midpoints of AD and BC, EF will be parallel to both AB and CD.

EF = Height between EF and DC and height between EF and AB are equal, because E and F are midpoints OF AD and BC and EF||AB||DC.

Let height between EF and DC and height between EF and AB be h cm.

Area of trapezium = 1/2 × (sum of parallel lines) × height

Now,

Area (Trap.ABFE) = 1/2 × (a + ) × h.

and

Area (Trap.ABFE) = 1/2 × (b + ) × h.

Area (Trap.ABFE) : Area (Trap.ABFE) = 1/2 × (a + ) × h : 1/2 × (b + ) × h

Area (Trap.ABFE) : Area (Trap.ABFE) = : = 3a + b : a + 3b

Area (Trap.ABFE) : Area (Trap.ABFE) = 3a + b : a + 3b

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