Q. 234.5( 4 Votes )
In the given figure, AB || CD. If ∠AOC = 30° and ∠OAB = 100°, then ∠OCD = ?
A. 130°
B. 150°
C. 80°
D. 100°
Answer :
From O, draw E such that OE || CD || AB.
OE || CD and OC is traversal.
So,
DCO + 
COE = 180 (co –interior angles)
x + 
COE = 180
COE = (180 – x)
Now, OE || AB and AO is the traversal.
BAO + 
AOE = 180 (co –interior angles)
BAO + 
AOC + 
COE = 180
100 + 30 + (180 – x) = 180
180 – x = 50
X = 180 – 50 = 130O
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