Q. 234.0( 7 Votes )

From the top of a

Answer :


Let height of the building be BD = 60 m


The height of the tower is ‘h’. The distance between the base of the building and the tower be ‘d’.


In Δ ADE,


tan 60°



d


BC = 20√3 = 20 (1.73) = 34.60 m


In Δ ABC,


tan 45°


1


AC = 34.60 m


Height of tower = AE – AC = 60 – 34.60 = 25.4 m


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