Q. 235.0( 3 Votes )
Find the ve
Vector equation of the line passing through and is
Therefore, vector equation of required line is
Now, equation of z-axis is
Therefore, the line is perpendicular to z-axis.
We can also do the last step as follows,
We know that if a1, b1, c1 are direction Ratios of a line perpendicular to line with direction Ratios a2, b2, c2 then,
a1a2 + b1b2 + c1c2 = 0
Equation of line:
If equation of line is,
Then, is a point through the line passes, and <a, b, c> is its direction ratio.
Direction Ratio of z-axis is <0, 0, 1>
Direction Ratio of line <-4, 2, 0>
a1a2 + b1b2 + c1c2 = (0)(-4) + (0)(2) + (1)(0)
= 0 + 0 + 0
So, the line is perpendicular to z – axis.
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