Q. 235.0( 3 Votes )

Find the ve

Answer :

Vector equation of the line passing through and is

Where, and

Therefore, vector equation of required line is

Now, equation of z-axis is


Therefore, the line is perpendicular to z-axis.

We can also do the last step as follows,

We know that if a1, b1, c1 are direction Ratios of a line perpendicular to line with direction Ratios a2, b2, c2 then,

a1a2 + b1b2 + c1c2 = 0

Equation of line:

If equation of line is,

Then, is a point through the line passes, and <a, b, c> is its direction ratio.

Direction Ratio of z-axis is <0, 0, 1>

Direction Ratio of line <-4, 2, 0>

a1a2 + b1b2 + c1c2 = (0)(-4) + (0)(2) + (1)(0)

= 0 + 0 + 0

= 0

So, the line is perpendicular to z – axis.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

Find the equationMathematics - Board Papers

Find the vector aMathematics - Board Papers

Write the vector Mathematics - Board Papers

Find the value ofMathematics - Board Papers

<span lang="EN-USMathematics - Board Papers