∠A + ∠B + ∠C=180° (Sum of angles of a triangle)
105° + 45° + ∠C=180°
Steps of Construction:
1.Draw a line segment BC of length 7cm.
2. Make an angle of 45° from B and an angle of 30° from C. The point where the rays meet is point A.
3.Draw a ray BZ making an acute angle with the line BC.Make 5 equal arcs starting from B, then B1 and so on till B5.
5.As we have to get the triangle 3/5 times of this triangle ABC.
6.From B3, draw a line parallel to B5C cutting BC at C’.
7.Draw another line from C’ parallel to AC cutting AB at A’.
8. A’BC’ is our required triangle.
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