Q. 235.0( 6 Votes )
A particle moves
Given: A particle moves along the curve x2 = 2y.
To Find: The point where ordinate increases at the same rate as abscissa increases.
Let, the point is (x, y), at which the ordinate increases at same rate as abscissa increases, i.e., .
Given curve is, x2 = 2y
Differentiating with respect to t we get,
⇒ 2x = 2 [as ]
⇒ x = 1
Putting x = 1 in the equation of curve we get,
⇒ 1 = 2y
⇒ y =
So, the point is (1, ).
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