Q. 235.0( 6 Votes )

A particle moves

Answer :

Given: A particle moves along the curve x2 = 2y.


To Find: The point where ordinate increases at the same rate as abscissa increases.


Let, the point is (x, y), at which the ordinate increases at same rate as abscissa increases, i.e., .


Given curve is, x2 = 2y


Differentiating with respect to t we get,



2x = 2 [as ]


x = 1


Putting x = 1 in the equation of curve we get,


1 = 2y


y =


So, the point is (1, ).


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