Q. 235.0( 6 Votes )

A particle moves

Answer :

Given: A particle moves along the curve x2 = 2y.

To Find: The point where ordinate increases at the same rate as abscissa increases.

Let, the point is (x, y), at which the ordinate increases at same rate as abscissa increases, i.e., .

Given curve is, x2 = 2y

Differentiating with respect to t we get,

2x = 2 [as ]

x = 1

Putting x = 1 in the equation of curve we get,

1 = 2y

y =

So, the point is (1, ).

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

The side of an eqMathematics - Board Papers

For the curve, <sMathematics - Board Papers

The money to be sMathematics - Board Papers

<span lang="EN-USMathematics - Board Papers

The side of an eqMathematics - Board Papers

The volume of a sMathematics - Board Papers