The area of the parallelogram shaped region ABCD is 100 sq units. P is midpoint of side BC; let us write how much area of triangular region ABP is.

The two parallelogram shaped regions ABCD and AEFG of which ∠A is common are equal in area and E lies on AB. Let’s prove that DE || FC.

If any triangle and any parallelogram are on the same base and between same parallels let us prove logically that the area of triangular region is half the area in the shape of parallelogram region.

PQRS is a parallelogram X and Y are the mid points of side PQ and SR respectively. Join diagonal SQ. Let us write area of the parallelogram shaped region XQRY : area of triangular region QSR.

ABDE is a parallelogram. F is midpoint of side ED. If area of triangular region ABD is 20 sq. unit, then let us write how much area of triangular region AEF is.

P is any a point on diagonal BD of parallelogram ABCD. Let’s prove that triangle APD = triangle CPD.

Two triangles ABC and ABD with equal area and stand on the opposite side of AB let’s prove that AB bisects CD.

E is any point on side DC of parallelogram ABCD, produced AE meets produced BC at the point F. Joined D, F. Let’s prove that

(i) triangle ADF = triangle ABE

(ii) triangle DEF = triangle BEC.

A, B, C, D are the mid points of sides PQ, QR, RS and SP respectively of parallelogram PQRS. If area of the parallelogram shaped region PQRS = 36 sq.cm then area of the region ABCD is

O is any a point inside parallelogram ABCD. If triangle AOB + triangle COD = 16 sq.cm, then area of the parallelogram shaped region ABCD is

DE is perpendicular on side AB from point D of parallelogram ABCD and BF is perpendicular on side AD from the point B; if AB = 10 cm, AD = 8 cm and DE = 6 cm, let us write how much length of BF is