Q. 223.9( 15 Votes )

# The weight of the

Answer :

Given, thickness = 5cm = 0.5dm

weight of empty box = 115.5 kg

weight of filled box = 880.5 kg

Length of inner side of box = 12dcm

breadth of inner side of box = 8.5 dcm

According to question, volume of rice inside the box = Inner capacity of box

weight of filled box-weight of empty box = length × breadth height

( 880.5-115.5)kg = 12×8.5×h

dcm^{3} = 102 h {1 cubic dcm rice is 1.5kg}

h =

h = 5 dcm

As, thickness of the box = 0.5dcm

So, outer length of box (L) = inner length + 2xthickness = 12 + 2×0.5 = 13 dcm

outer breadth of box(B) = inner breadth + 2Xthickness = 8.5 + 2×0.5 = 9.5 dcm

outer height of box(H) = inner height + 2X thickness = 5 + 2×0.5 = 6 dcm

As,Outer surface area = 2(LB + BH + LH)

= 2(13×9.5 + 9.5×6 + 6×13)

= 2(123.5 + 57 + 78)

= 2×285.5

= 517 dcm^{2}

According to question, cost of 1 dcm^{2} = Rs.1.5

So, cost of 517 dcm^{2} = Rs.(1.5×517)

= Rs 775.5

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