As A and B are independent events, so A’ and B’ are also independent.
We know that if A and B are independent events then
P(A ∩ B) = P(A)P(B)
As we have to find the probability of the event such that only one of them come to the school on time.
∴ P(required event) = P(A’ ∩ B) + P(A ∩ B’)
As A and B are independent events
⇒ ∴ P(required event) = P(A’)P(B) + P(A)P(B’)
As, P(A) = 3/7 ⇒ P(A’) = 1 - 3/7 = 4/7
And P(B) = 5/7 ⇒ P(B’) = 1 – 5/7 = 2/7
⇒ ∴ P(required event) =
P(required event) = 26/49
Benefit of coming school on time – by doing this we learn the value of time and importance of discipline
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