Answer :

As A and B are independent events, so A’ and B’ are also independent.

We know that if A and B are independent events then

P(A ∩ B) = P(A)P(B)

As we have to find the probability of the event such that only one of them come to the school on time.

∴ P(required event) = P(A’ ∩ B) + P(A ∩ B’)

As A and B are independent events

⇒ ∴ P(required event) = P(A’)P(B) + P(A)P(B’)

As, P(A) = 3/7 ⇒ P(A’) = 1 - 3/7 = 4/7

And P(B) = 5/7 ⇒ P(B’) = 1 – 5/7 = 2/7

⇒ ∴ P(required event) =

Thus,

P(required event) = 26/49

Benefit of coming school on time – by doing this we learn the value of time and importance of discipline

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