# Suppose a g

Let A be the event that girl will get 1 or 2

P(A) = =

Let B be the event that girl will get 3, 4, 5 or 6

P(B) = =

P(T/A) = Probability of exactly one till given she will get 1 or 2 =

P(T/B) = Probability of exactly one till given she will get 3, 4, 5 or 6

=

Hence the probability that she threw 3,4,5 or 6 with the ride is .

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