Answer :

*(2a + b)*We know,

^{3 }+ (2a - b)^{3}

(a+b)³=a³+3a²b+3ab²+b³

(a-b)³=a³-3a²b+3ab²-b³

= 16a

(a+b)³=a³+3a²b+3ab²+b³

(a-b)³=a³-3a²b+3ab²-b³

^{So, }= (8a^{3}+ 12a^{2}b + 3ab^{2 }+ b^{3})+(8a^{3 }- 12a^{2}b + 3ab^{2}- b^{3})= 16a

^{3}+ 6ab^{2}Rate this question :

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