Q. 223.9( 26 Votes )

Obtain all

Answer :

p(x) = 3x4 + 6x3 – 2x2 – 10x – 5


Since the two zeroes are


is a factor of 3x4 + 6x3 – 2x2 – 10x – 5


Therefore, we divide the given polynomial by



We know,
Dividend = (Divisor × quotient) + remainder


3 x4 + 6 x3 – 2x2 – 10 x – 5


3 x4 + 6 x3 – 2 x2 – 10 x – 5
As (a + b)2 = a2 + b2 + 2ab


3 x4 + 6 x3 – 2 x2 – 10 x – 5 = 3 (x + 1)2


Therefore, its zero is given by x + 1 = 0, x = −1


Hence, the zeroes of the given polynomial are and – 1, –1.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

When a polynomialRS Aggarwal - Mathematics

Find all the zeroRD Sharma - Mathematics