Q. 225.0( 2 Votes )

In Fig. 10.84, if A.

B.

C.

D.

Answer :

Given:


AP = 10 cm


OA = 6 cm


OB = 3 cm


Property : The tangent at a point on a circle is at right angles to the radius obtained by joining center and the point of tangency.


By above property, ∆PAO is right-angled at PAO (i.e., PAO = 90°) and PBO is right-angled at PBO (i.e., PBO = 90°).


Therefore by Pythagoras theorem in ∆PAO,


OP2 = OA2 + AP2


OP2 = 62 + 102


OP2 = 36 + 100


OP= √136


Now by Pythagoras theorem in ∆PBO,


OP2 = OB2 + BP2


BP2 = OP2 – OB2


BP2 = (√136) 2 – 32


BP2 = 136 – 9


BP= √127


Hence, BP= √127 cm

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses