Q. 225.0( 1 Vote )

# In a quadrilateral ABCD, ∠A+∠C is 2 times ∠B+∠D. If ∠A= 140° and f∠D = 60°, then ∠B=A. 60°B. 80°C. 120°D. None of these

Given that,

A = 140°

D = 60°

According to question,

A + C = 2 (B + D)

140 + C = 2 (B + 60°)

B = (C) + 10° (i)

We know,

A + B + C + D= 360°

140° + (C) + 10° + C + 60° = 360°

C = 150°

C = 100°

B = (100°) + 10°

= 60°

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