Q. 225.0( 1 Vote )

In a quadrilateral ABCD, A+C is 2 times B+D. If A= 140° and fD = 60°, then B=
A. 60°

B. 80°

C. 120°

D. None of these

Answer :

Given that,

A = 140°


D = 60°


According to question,


A + C = 2 (B + D)


140 + C = 2 (B + 60°)


B = (C) + 10° (i)


We know,


A + B + C + D= 360°


140° + (C) + 10° + C + 60° = 360°


C = 150°


C = 100°


B = (100°) + 10°


= 60°

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Surface Area and Volume of Right Circular Cone37 mins
Surface Area and Volume of Right Circular Cylinders42 mins
Surface Area and Volume of Spheres40 mins
RD Sharma | Surface areas and volumes of Cube & Cuboid33 mins
What an Atom holds?41 mins
Applications of Laws of Motion34 mins
Building blocks of brain27 mins
Quiz | Conservation of Momentum33 mins
Genius Quiz | Laws of Motion38 mins
Recently facts of 5th state of Matter: Bose Einstein Condensate52 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses