Q. 224.3( 3 Votes )
In a circle of ra A. 34 cm
B. 15 cm
C. 23 cm
D. 30 cm
Answer :
Given that,
AB || CD (Chords on opposite side of centre)
DO = BO (Radii)
OL and OM perpendicular bisector of CD and AB respectively
LM = 23 cm
AB = 16 cm
In 
OLB,
OB2 = OL2 + LB2
OL2 = 225
OL = 15 cm
OM = LM - OL
= 8 cm
In 
OMD,
OD2 = OM2 + MD2
MD2 = 225
MD = 15 cm
Now,
CD = 2 MD = 30 cm
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