# If<im

Letbe the required vector.

,

As, it is given thatis perpendicular to, therefore

a – 2b + c = 0 … (1)

Also,andare coplanar, therfore

1(-2c - b) - 1(c - a) + 1(b - ( -2a)) = 0

-2c - b - c + a + b + 2a = 0

2a + a – b + b – 2c – c = 0

3a – 3c = 0

a – c = 0 … (2)

Solving (1) and (2) we get,

a = b = c

So, a = 5

Hence

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