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We will solve this question by using planes method, first we will find the general equation of the plane containing all these points starting with the first point A,

a(x - 3) + b(y - 2) + c(z - 1) = 0

Now putting point C,

a(4 - 3) + b(2 - 2) + c( - 2 - 1) = 0

a + 0b – 3c = 0

Now putting point D,

a(6 - 3) + b(5 - 2) + c( - 1 - 1) = 0

3a + 3b - 2c = 0

Solving these equations by cross - multiplication method, we get,  a = 9λ, b = - 7λ, c = 3λ

The equation of the plane is,

9(x - 3) - 7(y - 2) + 3(z - 1) = 0

Putting point B in the equation,

9(4 - 3) - 7(x - 2) + 3(5 - 1) = 0

9 – 7x + 14 + 12 = 0

x = 5

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