Q. 225.0( 1 Vote )

# Find the particul

Answer :

The given differential equation is … (1)

Separating given differential equation, we get  On integrating, we get Let 2 – ey = t

- ey dy = dt - log (2 – ey) = log (x + 1) + C ... (2)

Putting y = 0, when x = 0 in (2), we get

- log (2 – 1) = log (0 + 1) + C

0 = 0 + C

C = 0

Equation (2) becomes - log (2 – ey) = log (x + 1)

log (x + 1) + log (2 – ey) = 0

log (x + 1) (2 – ey) = 0

(x + 1) (2 – ey) = e0 = 1

The solution is (x + 1) (2 – ey) = 1

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

Solve the followiRD Sharma - Volume 2

tan-1xMathematics - Exemplar

The number of solMathematics - Exemplar

Find the particulMathematics - Board Papers

Solve the followiRD Sharma - Volume 2

Find the particulMathematics - Board Papers