Q. 225.0( 1 Vote )

Find the particul

Answer :

The given differential equation is … (1)


Separating given differential equation, we get




On integrating, we get



Let 2 – ey = t


- ey dy = dt




- log (2 – ey) = log (x + 1) + C ... (2)


Putting y = 0, when x = 0 in (2), we get


- log (2 – 1) = log (0 + 1) + C


0 = 0 + C


C = 0


Equation (2) becomes - log (2 – ey) = log (x + 1)


log (x + 1) + log (2 – ey) = 0


log (x + 1) (2 – ey) = 0


(x + 1) (2 – ey) = e0 = 1


The solution is (x + 1) (2 – ey) = 1


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