Q. 225.0( 1 Vote )

Find:
<spa

Answer :

Using partial fraction:

On comparing:

A + B = 1 and 2B – A = 0

2B – A = 0

⇒ A = 2B

A + B = 1

⇒ 2B + B = 1

⇒ 3B = 1

Therefore,

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