Answer :

Step 1 : Draw a circle with radius 3 cm and centre O.

Step 2 : Draw any diameter AOB and Draw a radius OC such

such that BOC = 60°.

Step 3 : At C draw a perpendicular with OC and at A also

draw a perpendicular with OA.

**OR**

First we draw a right angle triangle

Step 1 : Draw a side AB of 4 cm with the help of scale.

Step 2 : Draw an perpendicular at point A with the help of compass. And cut 3 cm on it and named it as C.

Now we draw a triangle similar to right triangle whose sides are 3/5 times the corresponding sides.

Step 1 : Draw a line from point A below the AB.

Step 2 : Cut the line AD in 5 equal parts from point A and name them A_{1}, A_{2}, A_{3}, A_{4}, A_{5}

Step 3 : Meet the point A_{5} with B and make parallel to A_{5}B from A_{3}.

Step 4 : Make a line parallel to BC from B_{1}.

So, ∆ AB_{1}C_{1} the required triangle whose corresponding side

is 3/5 of the right angle triangle.

Rate this question :