# As observed

Given:

• AB = 100m

EAC = 45°

To find: CD, i.e. the distance between the boats

In ∆ ABC,

ACB = EAC = 45°

( alternate angles over parallel lines are equal)

tanACB = tan45° = 1

In ΔABC,

AB = BC = 100m

In ∆ ABD,

( alternate angles are equal)

BD = 100√3 m

So CD (distance between the boats) = BD – BC = 100(√3 – 1)m

= 73.2 m (apprx.)

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