Q. 225.0( 1 Vote )

# A box contains 10

As total articles = 10 + 6 = 16

P(good) =P(G) = 10/16

And P(defective)= P(D) = 6/16

As there it is not possible to select an item that is both good and defective.

P(good or Defective) = P(G D) = P(G) + P(D) = 16/16 = 1

As our answer does not directly seems to match with any option.

But option (a) is 64/64 = 1

option (a) is the only correct choice.

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