Q. 21 C4.8( 4 Votes )

O is any a point inside parallelogram ABCD. If triangle AOB + triangle COD = 16 sq.cm, then area of the parallelogram shaped region ABCD is
A. 8 sq. cm

B. 4 sq. cm

C. 32 sq. cm

D. 64 sq. cm

Answer :


If point O present inside parallelogram


Triangle AOB + triangle COD is half of the parallelogram


Then;


Triangle BOC + triangle DOA is another half of parallelogram


If triangle AOB + triangle COD = 16 sq. cm


Then area of parallelogram = 2×[ triangle AOB + triangle COD]


= 2× 16 sq. cm


= 32 sq. cm

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