Q. 21 C4.8( 4 Votes )

# O is any a point inside parallelogram ABCD. If triangle AOB + triangle COD = 16 sq.cm, then area of the parallelogram shaped region ABCD isA. 8 sq. cmB. 4 sq. cmC. 32 sq. cmD. 64 sq. cm

Answer :

If point O present inside parallelogram

Triangle AOB + triangle COD is half of the parallelogram

Then;

Triangle BOC + triangle DOA is another half of parallelogram

If triangle AOB + triangle COD = 16 sq. cm

Then area of parallelogram = 2×[ triangle AOB + triangle COD]

= 2× 16 sq. cm

= 32 sq. cm

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