# Without using distance formula, show that points (– 2, – 1), (4, 0), (3, 3) and (–3, 2) are the vertices of a parallelogram.

Let the point A( -2, -1) , B (4, 0) , C( 3, 3) and D( -3, 2) The slope of AB = The slope of CD = ⇒the slope of AB = Slope of CD

AB CD

The slope of BC = The slope of CD = The slope of BC = Slope of CD

BC CD

Thus the pair of opposite sides are quadrilateral are , hence ABCD is a parallelogram.

Thus A( -2, -1) , B (4, 0) , C( 3, 3) and D( -3, 2) are vertices of a parallelogram.

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