Q. 215.0( 4 Votes )

Using integration

Answer :

Given that, equation of the circle is x2 + y2 = 4.


The equation of the normal to the circle at (1, √3) is the equation of the line joining the points (1, √3) and (0,0).



y = √3 x (i)


equation of normal is y = √3 x.


Now, the equation of the tangent to the circle at (1, √3) is



√3 y – 3 = -x +1


(ii)


Putting y=0 , we get x=4


Hence, Δ AOB is formed by the positive x-axis and tangent and normal.



Now, Area of Δ AOB = Area of Δ AOC + Area of Δ ACB









= 2√3 sq. units


Hence, area of the triangle formed is 2√3 sq. units


OR


We have,


Where


Here, a =1 ,b=3 and f(x) = e2-3x+x2+1


hn=2


Now,












Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Evaluate:<span laMathematics - Board Papers

Evaluate:

Mathematics - Board Papers

Using integrationMathematics - Board Papers

Evaluate:

Mathematics - Board Papers

Evaluate:<span laMathematics - Board Papers

Evaluate:<span laMathematics - Board Papers