Answer :

**Concept Used:** Surface Area of cube = 6a^{2}

Volume of Cube = a^{3}

Surface area of cuboid = 2 (lb + bh + hl)

Volume of cuboid = lbh

Where a = edge of cube, l = length of the cuboid, b = breadth of the cuboid, and h = height of the cuboid.

**Given:** Volume of cubes = 64 cm^{3}

**Explanation:**

Let us find the edge of the cube first.

Volume of the cube = 64 cm^{3}

a^{3} = 64 cm^{3}

a = (64 cm^{3})^{1/3}

a = 4 cm

Now when the cubes are joined, new dimensions are,

Length of the cuboid = 8 cm

Breadth of the cuboid = 4 cm

Height of the cuboid = 4 cm

Now putting these values in the formula of volume of cuboid we get,

Surface Area of cuboid = 2(8×4 + 4×4 + 4×8)

Surface Area of cuboid = 2(32 + 16 + 32)

Surface Area of cuboid = 160 cm^{2}

Volume of cuboid = lbh

Volume of cuboid = 8 × 4 × 4

Volume of cuboid = 128 cm^{3}

**Hence, the surface area of resulting cuboid is 160 cm ^{2} and volume of resulting cuboid is 128 cm^{3}.**

Rate this question :

The dimensions ofRD Sharma - Mathematics

Three equal cubesRD Sharma - Mathematics

The length of theRD Sharma - Mathematics

If *V* is thRD Sharma - Mathematics

A rectangular tanRD Sharma - Mathematics

Given that 1 cubiRD Sharma - Mathematics

The breadth of a RD Sharma - Mathematics

A box with lid isRD Sharma - Mathematics

A cubical vessel RD Sharma - Mathematics