Answer :

Given, Length of tank = 2.5m

breadth of tank = 1.6m


Let height of tank be H m


Requirement of 1st family = 1200L = = 1.2 m3


Requirement of 2nd family = 1050L = = 1.05 m3


Requirement of 3rd family = 950L = = 0.95m3


As, 1m3 = 1000 L


According to question,


25% of the requirement is to be stored in a tank.


25% of Requirement of 1st family = = 0.3 m3


25% of Requirement of 2nd family = = 0.2625m3


25% of Requirement of 3rdfamily = = 0.2375m3


As, 25% of the total requirement of the water = volume of the land to be irrigated


0.3 + 0.2625 + 0.2375 = 2.5×1.6×H


0.8 = 4H


H = 0.2m


2nd part: breadth is increased by 4 dcm = 0.4 m


As, length = 2.5 m


Let the new depth be d m


again, As, 25% of the total requirement of the water = volume of the land to be irrigated


0.8 = 0.4×2.5×d


d


d = 0.8 m


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