Answer :

Given, Length of tank = 2.5m

breadth of tank = 1.6m

Let height of tank be H m

Requirement of 1st family = 1200L = = 1.2 m3

Requirement of 2nd family = 1050L = = 1.05 m3

Requirement of 3rd family = 950L = = 0.95m3

As, 1m3 = 1000 L

According to question,

25% of the requirement is to be stored in a tank.

25% of Requirement of 1st family = = 0.3 m3

25% of Requirement of 2nd family = = 0.2625m3

25% of Requirement of 3rdfamily = = 0.2375m3

As, 25% of the total requirement of the water = volume of the land to be irrigated

0.3 + 0.2625 + 0.2375 = 2.5×1.6×H

0.8 = 4H

H = 0.2m

2nd part: breadth is increased by 4 dcm = 0.4 m

As, length = 2.5 m

Let the new depth be d m

again, As, 25% of the total requirement of the water = volume of the land to be irrigated

0.8 = 0.4×2.5×d


d = 0.8 m

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