Q. 214.6( 12 Votes )

Solve the followi

Answer :

The given equation is-

After Cancelling out (b+2a) from both sides and taking reciprocal, we get-

-(4x2+4ax+2bx) = 2ab

4x2+4ax+2bx+2ab = 0

4x(x+a)+2b(x+a) = 0

2(2x+b)(x+a) = 0

(2x+b) = 0 or (x+a) = 0

x = (-b/2) or x = -a

Thus, the roots of the given equation are (-b/2) and -a.

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