Q. 215.0( 2 Votes )
Mark the correct alternative in the following:
Let 
, where 0 ≤ θ ≤ 2π. Then,
A. Det (A) = 0
B. Det (A) ∈ (2, ∞)
C. Det (A) ∈ (2, 4)
D. Det (A) ∈ [2, 4]
Answer :
A=
A=2[(
+1] 0≤(sin θ)2 ≤1
A∈2[1,2]
A∈[2,4]
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