Q. 213.6( 16 Votes )
In the given figu
We will have to make the following construction in the given figure:
Produce CB to D in such a way that BD=BC and join AD.
Now, in ∆ABC and ∆ABD,
∠ABC=∠ABD (each 90°)
∴ by S.A.S.
∆ABC ≅ ∆ABD
∠CAB=∠DAB and AC=AD (by c.p.c.t.)
∴ ∆ACD is equilateral triangle.
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