Q. 213.6( 16 Votes )

# In the given figu

We will have to make the following construction in the given figure:

Produce CB to D in such a way that BD=BC and join AD.

Now, in ∆ABC and ∆ABD,

BC=BD (constructed)

AB=AB (common)

ABC=ABD (each 90°)

by S.A.S.

∆ABC ∆ABD

CAB=DAB and AC=AD (by c.p.c.t.)

=x°+x°

=2x°

∆ACD is equilateral triangle.

AC=CD

AC=2BC

Hence, proved

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Eliminating India's Poverty48 mins
Poverty in India51 mins
Solving most Important Questions43 mins
People As Resources53 mins
Let's learn about Palampur47 mins
Revision on Angle sum Property of Triangles44 mins
Democracy - A Quick Insight55 mins
Significance of Newton's Laws in daily life42 mins
Work and Types of Work done40 mins
Subject Verb Agreement36 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

Each question conRS Aggarwal & V Aggarwal - Mathematics

In the given figuRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics