# In the given figure, AB || CD. If ∠ABO = 130° and ∠OCD = 110°, then ∠BOC = ?A. 50°B. 60°C. 70°D. 80°

According to question,

AB || CD

AF || CD (AB is produced to F, CF is traversal)

DCF=BFC=110o

Now, BFC + BFO = 180o(Sum of angles of Linear pair is 180o)

BFO = 180o – 110o = 70o

Now in triangle BOF, we have

ABO = BFO + BOF

130 = 70 + BOF

BOF = 130 – 70 =60o

So, BOC = 60o

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