Q. 214.0( 4 Votes )
In the given figure, AB || CD. If ∠ABO = 130° and ∠OCD = 110°, then ∠BOC = ?

A. 50°
B. 60°
C. 70°
D. 80°
Answer :
According to question,
AB || CD
AF || CD (AB is produced to F, CF is traversal)
DCF=
BFC=110o
Now, BFC +
BFO = 180o(Sum of angles of Linear pair is 180o)
BFO = 180o – 110o = 70o
Now in triangle BOF, we have
ABO =
BFO +
BOF
130 = 70 + BOF
BOF = 130 – 70 =60o
So, BOC = 60o
Rate this question :






















In the given figure, AB || CD. If ∠ABO = 130° and ∠OCD = 110°, then ∠BOC = ?
In Fig 8.117, p is a transversal to lines m and n, ∠2 = 120° and ∠5 = 60°. Prove that m||n.
In Fig 8.116, if l||m||n and ∠1 = 60°, find ∠2
In Fig. 8.136, if CP || DQ, then the measure of x is
In Fig. 8.142, if lines l and m are parallel, then the value of x is
In Fig. 8.138, if lines l and m are parallel, then x =
In Fig. 8.137, if AB|| HF and DE||FG, then the measure of ∠FDE is
In Fig. 8.132, if l1 || l2, what is the value of y?
In Fig. 8.134, if l || m, what is the value of x?