Q. 214.0( 4 Votes )

In the given figure, AB || CD. If ABO = 130° and OCD = 110°, then BOC = ?


A. 50°

B. 60°

C. 70°

D. 80°

Answer :

According to question,


AB || CD


AF || CD (AB is produced to F, CF is traversal)


DCF=BFC=110o


Now, BFC + BFO = 180o(Sum of angles of Linear pair is 180o)


BFO = 180o – 110o = 70o


Now in triangle BOF, we have


ABO = BFO + BOF


130 = 70 + BOF


BOF = 130 – 70 =60o


So, BOC = 60o

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