Answer :

Given: sin2θ cos2θ (1 + tan2θ) (1 + cot2θ) = λ

To find: λ

We know that 1 + tan2 θ = sec2 θ

And 1 + cot2 θ = cosec2 θ

sin2θ cos2θ (1 + tan2θ) (1 + cot2θ)

= sin2 θ cos2 θ sec2 θ cosec2 θ



sin2 θ cos2 θ (1 + tan2 θ) (1 + cot2 θ)

= sin2 θ cos2 θ sec2 θ cosec2 θ

λ = 1

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