Given: Now When x = 0 ⇒ y = 1⇒ln(1 + 1) = ln (1 + 0) + ln C⇒ ln 2 = ln C⇒ C = 2⇒2x2 – y2 + 1 = 0 (Particular Solution)

Q. 214.8( 4 Votes )

Find the particul

Answer :

Given:

Now When x = 0 ⇒ y = 1

⇒ln(1 + 1) = ln (1 + 0) + ln C

⇒ ln 2 = ln C

⇒ C = 2

⇒2x² – y² + 1 = 0 (Particular Solution)

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