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# Find the area of

To find the area enclosed by

y = √3x ...(i)

x2 + y2 = 16 ...(ii)

On solving the equation (i) and (ii),

Or x2 + = 16

Or 4x2 = 16

Or x2 = 4

Or x = Y = ± Equation (i) represents a parabola with vertex (0,0) and axis as x - axis.

Equation (ii) represent axis a circle with centre (4,0) and meets axes at (0,0) and (4,0).

They intersect at A (2, ) and C ( – 2, – ).

These are shown in the graph below: - Area of the region OAB = Area OAC + Area ACB       The area of the region in the first quadrant enclosed by x - axis, the line y = √3x and the circle x2 + y2 = 16 is Rate this question :

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