Answer :

Let us consider the above problem, by the following diagram, where 'A' depicts the aero plane, 'C' and 'D' depict two ends of river.

Now,

Angle of depression from plane to 'C' = ∠XAC = 45°

∠XAC = ∠ ACD = 45° = θ_{1}(say) [Alternate angles]

Angle of depression from plane to 'D' = ∠YAD = 60°

∠YAD = ∠ ADC = 60° = θ_{2}(say) [Alternate angles]

AP = Height at which aero plane is flying = 300 m

Now, In ΔACP and ΔADP

⇒ CP = 300 m

⇒DP = 100√3 m

⇒DP = 100(1.732)

⇒DP = 173.2 m

Now, distance between two banks, CD = CP + DP

⇒ CD = 300 + 173.2 = 473.2 m

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

Related Videos

Trigonometric Identities55 mins

Trigonometric Ratios of Specified Angles38 mins

Trigonometric Ratios46 mins

Heights and Distances - I54 mins

Heights and Distances - II45 mins

Extraction of Metal56 mins

Outcomes of Democracy43 mins

Refraction of Light-241 mins

Reflection of light-238 mins

Purification of Metals60 mins

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Expertsview all courses

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation