Q. 21

# AB and

Given that,

AB || CD (Chords on same side of centre)

OL and OM perpendicular bisector of CD and AB respectively

CL = LD = 6 cm

AM = MB = 3 cm

LM = 3 cm (Given)

In COL,

CO2 = OL2 + 62 (i)

In AOM,

AO2 = AM2 + OM2

= 2 + (OL + LM)2

= 9 + OL2 + 9 + 6O L

OL2 = AO2 - 18 - 6O L (ii)

Using (ii) in (i),

OL = 3 cm

Putting OL in (i),

AO2 =

AO = 35

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