# A cylindric

Given:

Height (h1) of cylindrical bucket = 32 cm

Radius (r1) of circular end of bucket = 18 cm

Height (h2) of conical heap = 24 cm

Let the radius of the circular end of conical heap be r2

The volume of sand in the cylindrical bucket will be equal to the volume of sand in the conical heap

Volume of sand in the cylindrical bucket = Volume of sand in conical heap

π r12 x h1 = 1/3  π x r22 x h2

π x (18)2 x 32 = 1/3 x π x r22 x 24

= 36 cm

l = 12 cm

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Trigo Marathon Part 146 mins
Trigo Marathon Part 245 mins
Application of Trigo Important Questions44 mins
History - Concept and Questions57 mins
Chemical Properties of Metal and Non Metal61 mins
Heights and Distances - II45 mins
Heights and Distances - I54 mins
Arithmetic Progression and 'nth' Term of AP55 mins
Extraction of Metal56 mins
Purification of Metals60 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses