Q. 204.4( 7 Votes )

# The ratio of the 11th term of the 18th term of an AP is 2:3. Find the ratio of the 5th term to the 21st term and also the ratio of the sum of the first five terms to the sum of the first 21 terms.

Answer :

**Given:** a_{11} : a_{18} = 2:3

**To find:** a_{5}:a_{21}

S_{5}:S_{21}

**Formula Used:**

Sum of “n” terms of an AP:

Where S_{n} is the sum of first n terms

nth term of an AP is:

a_{n =} a + (n - 1) d

Where a_{n} is the last term.

n = no of terms

a = first term

d = common difference

**Explanation:**

Let “a” and “d” the first term and common difference of an AP.

a_{11}:a_{18} = 2:3

a + 10d : a + 17d = 2:3

3a + 30d = 2a + 34d

a = 4d [ eqn 1]

a_{5} = a + 4d = 4d + 4d = 8d [ by eqn 1] [ Eqn 2]

a_{21} = a + 20d = 4d + 20d = 24d [ by eqn 1] [ Eqn 3]

now using the formula

= 30d

= 21( 14 )d

= 294

S_{5}:S_{21} = 30 : 294 = 5: 49

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