The largested squ

Given, sides of the right angled triangle are 3 cm, 4cm and 5 cm

Let BFDE is the largest square that can be inscribed in the right triangle ABC right angled at B

Also let BF = x cm so AF = 4-x cm

In Δ ABC and Δ AFD

∠ A= ∠ A common

∠ AFD = ∠ ABC (each 90°)

Δ ABC ∼ Δ AFD (by AA similarity)

So

⇒

⇒ 3 (4 - x) = 4x

⇒ 12 - 3x = 4x

⇒ 12 = 7x

⇒ cm

Length of square =