# The largested squ

Given, sides of the right angled triangle are 3 cm, 4cm and 5 cm

Let BFDE is the largest square that can be inscribed in the right triangle ABC right angled at B

Also let BF = x cm so AF = 4-x cm

In Δ ABC and Δ AFD

A= A common

AFD = ABC (each 90°)

Δ ABC Δ AFD (by AA similarity)

So

3 (4 - x) = 4x

12 - 3x = 4x

12 = 7x

cm

Length of square =

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