Answer :

Given, sides of the right angled triangle are 3 cm, 4cm and 5 cm



Let BFDE is the largest square that can be inscribed in the right triangle ABC right angled at B


Also let BF = x cm so AF = 4-x cm


In Δ ABC and Δ AFD


A= A common


AFD = ABC (each 90°)


Δ ABC Δ AFD (by AA similarity)


So




3 (4 - x) = 4x


12 - 3x = 4x


12 = 7x


cm


Length of square =


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