Answer :

Let hill be AB and tower be CD

Given: Height of the tower = 50 m

Hence, CD = 50 m

Angle of elevation of top of tower from the foot of a hill = 30°

Hence,CBD = 30°

Angle of elevation of top of the hill at the foot of tower = 60°

Hence,ADB = 60°

Now, In right ΔCBD, we have

BD = 50√3

In right ΔADB, we have

h = (50√3) × (√3)

h = 150 m

Hence, the height of the hill is 150m

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses