In the given figure AB || CD and O is a point joined with B and D, as shown in the figure such that ∠ABO = 35 and ∠CDO = 40°. Reflex ∠BOD = ?A. 255°B. 265°C. 275°D. 285°

Draw a line EF such that EF || AB and EF || CD crossing point O.

ABO + EOB = 180o(Sum of consecutive interior angles is 180o)

EOB = 180 – 35 = 145o

EF || AB such that AO is traversal.

CDO + EOD = 180o(Sum of consecutive interior angles is 180o)

EOD = 180 – 40 = 140o

BOD = EOB + EOD

= 145 + 140

= 285o

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