# In Fig. 9.45, if AB ⊥ BC, then x =A. 18B. 22C. 25D. 32

Given,

AB is perpendicular to BC so B = 90o

CED = 32o (Vertically opposite angles)

In

BDE + BED + DBE = 180o

x + 14o + 32o + x + 90o = 180o

2x = 44o

x = 22o

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